Many devices have a “sweet spot”; that is, a place, operational mode or setting where the device works best. Sports provide some of the best examples: baseball bats, tennis racquets and golf clubs all have a sweet spot (even if I could rarely find it!). Machines are the same way. Long ago I learned that a automobile engine runs best under conditions corresponding to a highway speed of something like 45 miles per hour. Wonder if that is still true? Centrifugal pumps certainly have a sweet spot; it’s even called the Best Efficiency Point (BEP). Generally speaking, when additional information is not available, I assume that the sweet spot of any device is near the middle of its operating range. The end points of an operating range are typically compromises in some way or other.
The G9 aperture can be varied between f2.8 and f8. The sweet spot in this range is somewhere between f4 and f5. After a few tests, I’d say that the sweet aperture of my own G9 is about f4.5.
A simple test was set up as shown here with a ruler

Here is a composite of the crops from the in-camera jpgs.
.jpg)
Remember, I was shooting raw + jpg but taking

What is the technical explanation for this sweet spot near f4.5 for the G9? The answer to this question appears to be related to the diffraction limit. I’m certainly no expert in diffraction but here are some handy links for a more detailed explanation and even some calculations.
Wikipedia has a detailed explanation of diffraction.
There is a good explanation of diffraction in digital photography and even a calculator to estimate the limiting aperture at http://www.cambridgeincolour.com/tutorials/digital-camera-sensor-size.htm.
In a final comparison, instead of the 100% pixel peeping monitor view, I made 8x10 sized, full frame matte prints on a Canon i9100 printer. Near the 8 inch mark, the 1/64 graduations are not detectable with the unaided eye from any of the variations! Even so, the f4.5 print from raw is obviously preferable to the others.
When the absolute maximum quality image is required, I’ll be tending to shoot my G9 at f4.5 but the larger and smaller apertures are still very useable – and I do drive faster (and slower) than 45 mph!
Note: Knowing I would be writing that raw revealed more details than jpg, and anticipating the grief that would come my way for doing so, I suddenly remembered that when the G9 is set for raw + jpg, the in-camera jpg is compressed at the “Fine” level whereas in pure jpg mode the “Super Fine” compression is available. I repeated the test shots in jpg only, using “Super Fine” compression mode. The results are the same: f4.5 is the sweet spot and raw reveals more detail than jpg; however, Super Fine compression does reveal slightly more detail than Fine compression. I believe that the difference in the raw and jpg shots is not “raw vs jpg” but is instead an indication of the in-camera noise reduction that is done on the in-camera jpg even at ISO 80. The raw file did not have any noise reduction applied. Should noise reduction have been applied to the raw files? Well, you were looking at 100% crops, would you apply noise reduction?
2 comments:
OK, very interesting, I use mine for some macro photos of my wife's jewelry for the web. I am going to use 4.5 next time and see if I can get the same results. I have been using f8 until I read this, thanks for your analysis.
Great blog, thanks!
Post a Comment